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Extremum, Increase and Decrease sections – Extremum to a function with a third root in a closed interval – Exercise 6878

Exercise

Determine the absolute extrema for the following function

f(x)=x^2\sqrt[3]{6x-7}

On the closed interval

[-1,2]

Final Answer

\max_{[-1,2]}f(x)=f(2)=6.84

\min_{[-1,2]}f(x)=f(-1)=-2.35

Solution

Coming soon…

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