fbpx
calculus online - Free exercises and solutions to help you succeed!

Extremum, Increase and Decrease Sections – Calculate absolute minimum and maximum in a closed interval – Exercise 5488

Exercise

Find the minimum and maximum points of the function

f(x)=\frac{x^2}{5e^{2x}}

In the interval

[-\frac{1}{2},2]

Final Answer


x=-\frac{1}{2}, x=0

Solution

Coming soon…

Share with Friends

Leave a Reply