Calculus-Online » Calculus Solutions » One Variable Functions » Extremum, Increase and Decrease Sections » Extremum, Increase and Decrease sections – Extremum to a polynomial function in an absolute value in a closed interval – Exercise 6918

Extremum, Increase and Decrease sections – Extremum to a polynomial function in an absolute value in a closed interval – Exercise 6918

Determine the absolute extrema for the following function

$f(x)=|x^2-3x+2|$

On the closed interval

$[-10,10]$

Final Answer

$\max_{[-10,10]}f(x)=132$

$\min_{[-10,10]}f(x)=0$

Coming soon…

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