Exercise
Solve the square inequality:
x^2+3x+5>0
Final Answer
Solution
x^2+3x+5>0
It is a square inequality. its coefficients are:
a=1, b=3, c=5
The coefficient of the squared expression (a) is positive, so the parabola (quadratic equation graph) “smiles” (= bowl-shaped). The sign of the inequality means we are looking for the sections the parabola is above the x-axis. We find the solutions (= zeros = roots) of the quadratic equation using the quadratic formula. Putting the coefficients in the formula gives us
x_{1,2}=\frac{-3\pm \sqrt{3^2-4\cdot 1\cdot 5}}{2\cdot 1}=
=\frac{-3\pm \sqrt{-11}}{2}
We got a negative number inside the root, so there is no real solution to the quadratic equation, i.e. its graph does not pass through the x-axis. Because she is “smiling”, she is always above the x-axis. Hence, the solution of the inequality is all x.
The graph of the equation:
y=x^2+3x+5
looks like this:
You can see that the graph is indeed above the x-axis for each x.
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