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Proving Derivative Existence – A function with parameters – Exercise 1231

Exercise

Given the function (a and b parameters)

f(x) = \begin{cases} a\sqrt{x+1}, &\quad 0\leq x\leq 3 \\ 5-bx, &\quad 3<x\leq 6\\ \end{cases}

For which values of the function parameters is it differentiable at point x=3?

Final Answer


a=4, b=-1

Solution

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