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Proving Derivative Existence – A function with a polynomial and a square root – Exercise 1140

Exercise

Given the function

f(x) = \begin{cases} 2x^2, &\quad x\leq 1 \\ 2\sqrt{x}, &\quad x >1\\ \end{cases}

Is it differentiable at point x=1?

Final Answer


The function is not differentiable at x=1.

Solution

Coming soon…

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