# Improper Integral – A rational function on an infinite interval – Exercise 6612

Exercise

Evaluate the integral

$$\int_{2}^{\infty} \frac{1}{x^2(x^2-1)} dx$$

Final Answer

$$\int_{2}^{\infty} \frac{1}{x^2(x^2-1)} dx=-\frac{1}{2}+\frac{1}{2}\ln 3$$

Solution

Coming soon…

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