Definite Integral – A quotient of functions with absolute value on a symmetric interval – Exercise 6431 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral \int_{-1}^1 \frac{x{(|x|+1)}^7}{x^4+x^2+1} dx Final Answer Show final answer \int_{-1}^1 \frac{x{(|x|+1)}^7}{x^4+x^2+1} dx=0 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – A quotient of functions with a root on a finite interval – Exercise 6425 Next PostDefinite Integral – x in absolute value on a finite interval – Exercise 6434 You Might Also Like Definite Integral – An exponential function on a finite interval – Exercise 6421 July 8, 2019 Definite Integral – A quotient of exponential functions on a symmetric interval – Exercise 6439 July 8, 2019 Definite Integral – Finding area between 2 polynomials – Exercise 7009 August 21, 2019 Definite Integral – Finding area between 3 functions – Exercise 5371 May 15, 2019 Definite Integral – A polynomial in absolute value on a finite interval – Exercise 6436 July 8, 2019 Definite Integral – x in absolute value on a finite interval – Exercise 6434 July 8, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Definite Integral – A quotient of exponential functions on a symmetric interval – Exercise 6439 July 8, 2019