fbpx
calculus online - Free exercises and solutions to help you succeed!

Global Extremum – Domain of ellipse – Exercise 4749

Exercise

Find the maximum value and the minimum value of the function

z(x,y)=x-2y

In the domain:

D=\{ (x,y): \frac{x^2}{4}+y^2\leq 2\}

Final Answer


\max_D z(2,-1) = 4,\min_D z(-2,1) =-4

Solution

Coming soon…

Share with Friends

Leave a Reply