Global Extremum – Domain of ellipse – Exercise 4749 Post category:Global Extremum Post comments:0 Comments Exercise Find the maximum value and the minimum value of the function z(x,y)=x-2y In the domain: D=\{ (x,y): \frac{x^2}{4}+y^2\leq 2\} Final Answer Show final answer \max_D z(2,-1) = 4,\min_D z(-2,1) =-4 Solution Coming soon… Share with Friends Read more articles Previous PostGlobal Extremum – Domain of lines – Exercise 3443 Next PostGlobal Extremum – Domain of ellipse – Exercise 5392 You Might Also Like Global Extremum – Domain of a function with fixed negative powers – Exercise 6551 July 23, 2019 Global Extremum – Domain of a circle – Exercise 6543 July 15, 2019 Global Extremum – Domain of a circle – Exercise 6538 July 15, 2019 Global Extremum – Domain of lines – Exercise 5529 June 9, 2019 Global Extremum – Domain of ellipse – Exercise 5392 May 15, 2019 Global Extremum – Domain of lines – Exercise 3443 February 21, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ