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Calculating Triple Integrals – Bounded by surfaces – Exercise 4573

Exercise

Calculate the integral

\int\int\int_T \frac{1}{{(1+x+y+z)}^3} dxdydz

Where T is bounded by the surfaces

x=0,y=0,z=0,x+y+z=1

Final Answer


\int\int\int_T \frac{1}{{(1+x+y+z)}^3} dxdydz=\frac{1}{2}\ln 2-\frac{5}{16}

Solution

Coming soon…

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