Vectors – Calculate the length of diagonals of a parallelogram – Exercise 4469

Exercise

Calculate the lengths of the parallelogram diagonasl built on the vectors

$\vec{a}=5\vec{p}+2\vec{q}$

$\vec{b}=\vec{p}-3\vec{q}$

Given that

$|\vec{p}|=2\sqrt{2}, |\vec{q}|=3$

And the angle between them is equal to 45 degrees.

Final Answer

$|\vec{a}+\vec{b}|=15$

$|\vec{b}-\vec{a}|=\sqrt{593}$

Solution

Coming soon…

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