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# Gradient – Calculate scalar field gradient and direction – Exercise 4257

Exercise

Calculate the gradient of the scalar field

$$u=xyz$$

At point (2,1,1)

And calculate its direction at this point.

Final Answer

$$\nabla u(2,1,1)=\vec{i}+2\vec{j}+2\vec{k}$$

$$\hat{\nabla} u(2,1,1)=\frac{1}{3}\vec{i}+\frac{2}{3}\vec{j}+\frac{2}{3}\vec{k}$$

### Solution

Coming soon…

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