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Surface Integrals – On a cone – Exercise 4068

Exercise

Calculate the integral

\int\int_S (x^2+y^2+z^2) ds

Where S is part of the cone

z=\sqrt{x^2+y^2}

That is on the circle

x^2+y^2\leq 2x

Final Answer

\int\int_S (x^2+y^2+z^2) ds=3\sqrt{2}\pi

Solution

Coming soon…

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