Calculus-Online » Calculus Solutions » Vector Functions » Different Representations of Curves » Different Representation of Curves – Switch from Cartesian to vector – Exercise 3793

Different Representation of Curves – Switch from Cartesian to vector – Exercise 3793

Exercise

Given the curve

$\sqrt{x}+\sqrt{y}=1$

Where

$x\geq 0,y\geq 0$

Present the curve in the vector presentation.

Final Answer

$\vec{r}(t)=t^2\vec{i}+{(1-t)}^2\vec{j}$

Solution

Coming soon…

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