# Different Representation of Curves – Switch from Cartesian to vector – Exercise 3793

Exercise

Given the curve

$$\sqrt{x}+\sqrt{y}=1$$

Where

$$x\geq 0,y\geq 0$$

Present the curve in the vector presentation.

$$\vec{r}(t)=t^2\vec{i}+{(1-t)}^2\vec{j}$$