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Calculating Limit of Function – A rational function – Exercise 347

Exercise

Evaluate the following limit:

\lim _ { x \rightarrow \frac{1}{2} } \frac {8 x^2 - 2 x - 1} {4 x^2 - 8 x + 3}

Final Answer


\lim _ { x \rightarrow \frac{1}{2} } \frac {8 x^2 - 2 x - 1} {4 x^2 - 8 x + 3} = - \frac {3}{2}

Solution

Coming soon…

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