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Domain of One Variable Function – A function with polynom inside a square root – Exercise 2421

Exercise

Determine the domain of the function:

f(x)=\sqrt{1-x^2}

Final Answer


-1\leq x\leq 1

Solution

Let’s find the domain of the function:

f(x)=\sqrt{1-x^2}

There is a square root, so we need the expression inside the root to be non-negative:

1-x^2\geq 0

It is a square inequality. The roots of the quadratic equation:

1-x^2=0

are

x_1=1, x_2=-1

Also, the coefficient of the square expression is negative (-1), so the graph looks like an inverted parabola (= inverted bowl = “crying”).

It looks like this:

Exercise 2 - תחום הגדרה

Back to inequality:

1-x^2\geq 0

We need to check when the equation we solved is not negative, i.e. when the graph is not below the x-axis. And one can see from the graph that this happens when the following holds

-1\leq x\leq 1

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