# Calculating Limit of Series – A polynomial divided by an exponential – Exercise 764

Exercise

Find the limit

$$\lim _ { n \rightarrow \infty} \frac{{(n^2+1)}^{98}}{4^n}$$

$$\lim _ { n \rightarrow \infty} \frac{{(n^2+1)}^{98}}{4^n}=0$$

Solution

Coming soon…

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